(b^3-2b^2+b)-(b^2+3b-1)=0

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Solution for (b^3-2b^2+b)-(b^2+3b-1)=0 equation: 


Simplifying
(b3 + -2b2 + b) + -1(b2 + 3b + -1) = 0

Reorder the terms:
(b + -2b2 + b3) + -1(b2 + 3b + -1) = 0

Remove parenthesis around (b + -2b2 + b3)
b + -2b2 + b3 + -1(b2 + 3b + -1) = 0

Reorder the terms:
b + -2b2 + b3 + -1(-1 + 3b + b2) = 0
b + -2b2 + b3 + (-1 * -1 + 3b * -1 + b2 * -1) = 0
b + -2b2 + b3 + (1 + -3b + -1b2) = 0

Reorder the terms:
1 + b + -3b + -2b2 + -1b2 + b3 = 0

Combine like terms: b + -3b = -2b
1 + -2b + -2b2 + -1b2 + b3 = 0

Combine like terms: -2b2 + -1b2 = -3b2
1 + -2b + -3b2 + b3 = 0

Solving
1 + -2b + -3b2 + b3 = 0

Solving for variable 'b'.

The solution to this equation could not be determined.

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